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Learn the step-by-step solution to a JEE Mains 2025 Physics PYQ on electric charge distribution over an irregular metallic conductor. Includes video explanation and detailed concept breakdown.

JEE Mains 2025 Physics: Electric Charge Distribution on Irregular Metallic Disk (Solved PYQ)

Preparing for JEE Mains 2025 Physics? This post breaks down a common but tricky problem from the topic of Electrostatics – Surface Charge Density and Curvature. Understand how charge distributes on an irregular metallic conductor and avoid common mistakes in exams.

🎥 Watch the Full Video Solution

This video explains the complete step-by-step solution. Watch it first before reading the detailed breakdown below:

Question

Electric charge is transferred to an irregular metallic disk as shown in the figure. If σ₁, σ₂, σ₃, and σ₄ are the surface charge densities at the given points, choose the correct answer from the options below:

  • A. σ₁ > σ₃ ; σ₂ = σ₄
  • B. σ₁ > σ₂ ; σ₃ > σ₄
  • C. σ₁ > σ₃ ≥ σ₂ = σ₄
  • D. σ₁ < σ₃ < σ₂ = σ₄
  • E. σ₁ = σ₂ = σ₃ = σ₄

Options:

  1. A and C Only
  2. D and E Only
  3. A, B and C Only
  4. B and C Only

Detailed Step-by-Step Solution

Step 1: Understand the Concept of Charge Distribution

On a metallic conductor in electrostatic equilibrium, the surface charge density is not uniform if the object has an irregular shape. The charge density is directly related to the local curvature of the surface:

σ ∝ Curvature

Sharper points (higher curvature) accumulate more charge, while flatter regions have less surface charge density.

Step 2: Analyze the Given Figure

  • σ₁ is located at the sharpest point at the top → Maximum curvature
  • σ₃ is at the bottom tip → Less sharp than σ₁
  • σ₂ and σ₄ are on the sides → Flat regions with equal curvature

Step 3: Compare the Surface Charge Densities

Based on curvature, the correct order is:

σ₁ > σ₃ > σ₂ = σ₄

Step 4: Match the Options

  • A: σ₁ > σ₃ ; σ₂ = σ₄ → ✅ Correct
  • B: σ₁ > σ₂ ; σ₃ > σ₄ → ✅ Correct (since σ₃ > σ₄)
  • C: σ₁ > σ₃ ≥ σ₂ = σ₄ → ✅ Correct
  • D: σ₁ < σ₃ < σ₂ = σ₄ → ❌ Incorrect
  • E: σ₁ = σ₂ = σ₃ = σ₄ → ❌ Incorrect

Step 5: Final Answer

The correct answer is:

Option (3): A, B and C Only

Conclusion

This problem illustrates how surface charge density varies with curvature on a conductor. Remember: sharper points accumulate more charge. This concept is frequently tested in JEE Mains and Advanced.

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