Errors in Measurement for Engineering Physics

Follow our Social Media Pages

Question and Answer from Errors in Measurement

1. A certain body weights 22.42 gm and has a measured volume of 4.7 cc. The possible error in the measurement of mass and volume are 0.01 gm and 0.1 cc. Then maximum error in the density will be (a) 22 %, (b) 2 %, (c) 0.2 %, (d) 0.02 %

Show Answer

Maximum Error in Density — Solution

Problem

A body has mass m = 22.42 g and volume V = 4.7 cc. Possible errors are Δm = 0.01 g and ΔV = 0.1 cc. Find the maximum percentage error in density. (a) 22 % (b) 2 % (c) 0.2 % (d) 0.02 %

Solution

Density: ρ = m / V

Maximum fractional error in ρ (additive for independent errors):

Δρ / ρ = (Δm / m) + (ΔV / V)
    

Compute fractional errors:

Δm / m = 0.01 / 22.42 ≈ 0.000446
ΔV / V = 0.1  / 4.7   ≈ 0.021277
Δρ / ρ ≈ 0.000446 + 0.021277 = 0.021723
Percentage error = 0.021723 × 100 ≈ 2.17 %
    

Therefore the nearest choice is: (b) 2 %.

2. If the error in the measurement of radius of a sphere is 2 %, then the error in the determination of volume of the sphere will be (a) 4 %, (b) 6 %, (c) 8%, (d) 2%

Show Answer

Error in Volume of a Sphere — Solution

Problem

If the error in the measurement of radius of a sphere is 2 %, then the error in the determination of volume of the sphere will be:

(a) 4 %   (b) 6 %   (c) 8 %   (d) 2 %

Solution

Volume of a sphere: V = (4/3)π r³

Relative (percentage) error in volume when radius has error is:

ΔV / V = 3 · (Δr / r)

Given Δr / r = 2%, therefore

ΔV / V = 3 × 2% = 6%

Correct option: (b) 6 %

3. In an experiment four quantities a, b, c and d are measured with percentage error 1%, 2%, 3% and 4% respectively. Quantity P is calculated as follows % error in P is (a) 10 %, (b) 7 %, (c) 4%, (d) 14%

Show Answer

Step-by-step: Percentage Error in P

Problem (restated)

Measured percentage errors:

  • a : 1%
  • b : 2%
  • c : 3%
  • d : 4%

Quantity:

P = (a³ b²) / (c d)

Step-by-step solution

  1. Write P:
    P = a³ · b² · c⁻¹ · d⁻¹
  2. Take natural log (to use differential rule):
    ln P = 3 ln a + 2 ln b − ln c − ln d
  3. Differentiate (relative errors):
    dP / P = 3 (da / a) + 2 (db / b) − (dc / c) − (dd / d)

    For maximum percentage error we take absolute contributions (add magnitudes):

  4. Convert to percentage form:
    %ΔP ≈ 3·%Δa + 2·%Δb + 1·%Δc + 1·%Δd
  5. Substitute given percentages:
    3 × 1% = 3%
    2 × 2% = 4%
    1 × 3% = 3%
    1 × 4% = 4%
            
  6. Add them to get total percentage error:
    %ΔP = 3% + 4% + 3% + 4% = 14%
Final answer: 14% — option (d).

4. The percentage errors in the measurements of mass and speed are 2% and 3% respectively. The error in kinetic energy obtained by measuring mass and speed will be (a)12 %, (b) 10 %, (c) 8%, (d) 2%

Show Answer

Error in Kinetic Energy — Solution

Problem

The percentage errors in the measurements of mass and speed are 2% and 3% respectively. The error in kinetic energy obtained by measuring mass and speed will be:

(a) 12 %   (b) 10 %   (c) 8 %   (d) 2 %

Solution

Kinetic energy of a body is

K = (1/2) m v²

Take relative (fractional) errors. For a product/power:

ΔK / K ≈ Δm / m + 2 · (Δv / v)

Given:

Δm / m = 2%  (mass error)
Δv / v = 3%  (speed error)

Substitute:

ΔK / K ≈ 2% + 2 × 3% = 2% + 6% = 8%

Therefore the correct option is: (c) 8 %.

5. In an experiment refractive index of glass was observed to be 1.56, 1.45, 1.54, 1.44, 1.53 and 1.54. Calculate (i) mean absolute error, (ii) relative error and (iii) percentage error.

6. In an experiment to measure the specific gravity of a liquid, the observed values were:
0.98, 1.02, 0.97, 1.03, 0.99

Calculate:
(i) Mean value
(ii) Mean absolute error
(iii) Relative error
(iv) Percentage error

7. A student measures the focal length of a concave mirror five times and obtains the following values (in cm):
14.5, 15.2, 14.8, 15.0, 14.9

Calculate:
(i) Mean focal length
(ii) Mean absolute error
(iii) Relative error
(iv) Percentage error

Leave a Reply

Your email address will not be published. Required fields are marked *