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Question and Answer from Errors in Measurement
1. A certain body weights 22.42 gm and has a measured volume of 4.7 cc. The possible error in the measurement of mass and volume are 0.01 gm and 0.1 cc. Then maximum error in the density will be (a) 22 %, (b) 2 %, (c) 0.2 %, (d) 0.02 %
A body has mass m = 22.42 g and volume V = 4.7 cc.
Possible errors are Δm = 0.01 g and ΔV = 0.1 cc.
Find the maximum percentage error in density. (a) 22 % (b) 2 % (c) 0.2 % (d) 0.02 % Density: Maximum fractional error in ρ (additive for independent errors): Compute fractional errors: Therefore the nearest choice is: (b) 2 %.Show Answer
Problem
Solution
ρ = m / V
Δρ / ρ = (Δm / m) + (ΔV / V)
Δm / m = 0.01 / 22.42 ≈ 0.000446
ΔV / V = 0.1 / 4.7 ≈ 0.021277
Δρ / ρ ≈ 0.000446 + 0.021277 = 0.021723
Percentage error = 0.021723 × 100 ≈ 2.17 %
2. If the error in the measurement of radius of a sphere is 2 %, then the error in the determination of volume of the sphere will be (a) 4 %, (b) 6 %, (c) 8%, (d) 2%
If the error in the measurement of radius of a sphere is 2 %, then the error in the determination of volume of the sphere will be: (a) 4 % (b) 6 % (c) 8 % (d) 2 % Volume of a sphere: Relative (percentage) error in volume when radius has error is: Given Correct option: (b) 6 %Show Answer
Problem
Solution
V = (4/3)π r³ΔV / V = 3 · (Δr / r)
Δr / r = 2%, thereforeΔV / V = 3 × 2% = 6%
3. In an experiment four quantities a, b, c and d are measured with percentage error 1%, 2%, 3% and 4% respectively. Quantity P is calculated as follows % error in P is (a) 10 %, (b) 7 %, (c) 4%, (d) 14%
Measured percentage errors: Quantity: For maximum percentage error we take absolute contributions (add magnitudes):Show Answer
Problem (restated)
P = (a³ b²) / (c d)
Step-by-step solution
P = a³ · b² · c⁻¹ · d⁻¹
ln P = 3 ln a + 2 ln b − ln c − ln d
dP / P = 3 (da / a) + 2 (db / b) − (dc / c) − (dd / d)
%ΔP ≈ 3·%Δa + 2·%Δb + 1·%Δc + 1·%Δd
3 × 1% = 3%
2 × 2% = 4%
1 × 3% = 3%
1 × 4% = 4%
%ΔP = 3% + 4% + 3% + 4% = 14%
4. The percentage errors in the measurements of mass and speed are 2% and 3% respectively. The error in kinetic energy obtained by measuring mass and speed will be (a)12 %, (b) 10 %, (c) 8%, (d) 2%
The percentage errors in the measurements of mass and speed are 2% and 3% respectively.
The error in kinetic energy obtained by measuring mass and speed will be: (a) 12 % (b) 10 % (c) 8 % (d) 2 % Kinetic energy of a body is Take relative (fractional) errors. For a product/power: Given: Substitute: Therefore the correct option is: (c) 8 %.Show Answer
Problem
Solution
K = (1/2) m v²
ΔK / K ≈ Δm / m + 2 · (Δv / v)
Δm / m = 2% (mass error)
Δv / v = 3% (speed error)
ΔK / K ≈ 2% + 2 × 3% = 2% + 6% = 8%
5. In an experiment refractive index of glass was observed to be 1.56, 1.45, 1.54, 1.44, 1.53 and 1.54. Calculate (i) mean absolute error, (ii) relative error and (iii) percentage error.
6. In an experiment to measure the specific gravity of a liquid, the observed values were:
0.98, 1.02, 0.97, 1.03, 0.99
Calculate:
(i) Mean value
(ii) Mean absolute error
(iii) Relative error
(iv) Percentage error
7. A student measures the focal length of a concave mirror five times and obtains the following values (in cm):
14.5, 15.2, 14.8, 15.0, 14.9
Calculate:
(i) Mean focal length
(ii) Mean absolute error
(iii) Relative error
(iv) Percentage error
